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GATE CH Formula Sheet

A single, organized reference for every core GATE Chemical Engineering formula, 218+ formulas from the Antoine equation and LMTD to Reynolds number and reaction kinetics, grouped by topic with variable definitions and links back to the full topic guide or calculator. Built for quick lookup during revision.

Core Transport

Diffusion Mass Transfer Fundamentals

8 formulas · Open the full topic guide

NA=DABdCAdz+xA(NA+NB)N_A = -D_{AB}\dfrac{dC_A}{dz} + x_A(N_A+N_B)

Fick's first law with the bulk-flow (convective) term, reduces to simple diffusion only when NA + NB = 0

NA=DABPRTz(1yA2)lm(yA1yA2)N_A = \dfrac{D_{AB}P}{RTz(1-y_{A2})_{lm}}\left(y_{A1}-y_{A2}\right)

Diffusion of A through stagnant B, flux enhanced by the log-mean mole fraction of inert B, (1−yA)lm

(1yA)lm=(1yA2)(1yA1)ln[1yA21yA1](1-y_A)_{lm} = \dfrac{(1-y_{A2})-(1-y_{A1})}{\ln\left[\frac{1-y_{A2}}{1-y_{A1}}\right]}

Log-mean mole fraction of stagnant component B, used in the stagnant-film flux equation

NA=NB=DABRTz(pA1pA2)N_A = -N_B = \dfrac{D_{AB}}{RTz}(p_{A1}-p_{A2})

Equimolar counterdiffusion flux, a simpler linear form, no log-mean correction needed

Sh=kcLDABSh = \dfrac{k_c L}{D_{AB}}

Sherwood number, ratio of convective to diffusive mass transfer, analogous to the Nusselt number

Sc=μρDABSc = \dfrac{\mu}{\rho D_{AB}}

Schmidt number, ratio of momentum to mass diffusivity, analogous to the Prandtl number

Sh=0.023Re0.8Sc1/3Sh = 0.023\,Re^{0.8}Sc^{1/3}

Mass-transfer analog of the Dittus-Boelter correlation, for turbulent flow in a pipe or duct

kcv=Stm=f2Sc2/3\dfrac{k_c}{v} = St_m = \dfrac{f}{2}\,Sc^{-2/3}

Chilton-Colburn analogy connecting the mass transfer Stanton number to the Darcy/Fanning friction factor

Fluid Mechanics

14 formulas · used across 16 PYQ questions tagged this topic · Open the full topic guide

P=P0+ρghP = P_0 + \rho g h

Hydrostatic pressure at depth h below a free surface

A1v1=A2v2A_1 v_1 = A_2 v_2

Continuity equation for incompressible flow

Pρg+v22g+z=const.\dfrac{P}{\rho g} + \dfrac{v^2}{2g} + z = \text{const.}

Bernoulli's equation along a streamline (energy per unit weight)

Re=ρvDμRe = \dfrac{\rho v D}{\mu}

Reynolds number, Re < 2100 laminar, 2100–4000 transitional, > 4000 turbulent (circular pipe)

Also in: Reynolds

ΔP=32μLvD2\Delta P = \dfrac{32\mu L v}{D^2}

Hagen-Poiseuille equation, laminar pressure drop in a pipe (Q = πΔPD⁴/128μL)

Also in: Reynolds

f=64Ref = \dfrac{64}{Re}

Darcy friction factor for laminar flow

ΔP=f(LD)(ρv22)\Delta P = f\left(\dfrac{L}{D}\right)\left(\dfrac{\rho v^2}{2}\right)

Darcy-Weisbach equation for frictional pressure drop (use the Moody chart for turbulent f)

Also in: Friction Factor, Pressure Drop

fDarcy=4×fFanningf_{Darcy} = 4 \times f_{Fanning}

Conversion between the two common friction-factor conventions, a frequent source of factor-of-4 errors

ΔPL=150(1ε)2μvε3dp2+1.75(1ε)ρv2ε3dp\dfrac{\Delta P}{L} = \dfrac{150(1-\varepsilon)^2 \mu v}{\varepsilon^3 d_p^2} + \dfrac{1.75(1-\varepsilon)\rho v^2}{\varepsilon^3 d_p}

Ergun equation for pressure drop through a packed bed (ε = voidage, dp = particle diameter)

Q=CdA22ΔPρ[1(A2/A1)2]Q = C_d A_2 \sqrt{\dfrac{2\Delta P}{\rho\left[1-(A_2/A_1)^2\right]}}

Venturi/orifice meter flow rate from measured pressure drop

NPSHa=PatmPvaporρg+hshfNPSH_a = \dfrac{P_{atm}-P_{vapor}}{\rho g} + h_s - h_f

Available Net Positive Suction Head, must exceed the pump's required NPSH to avoid cavitation

Number of π groups=nm\text{Number of } \pi \text{ groups} = n - m

Buckingham Pi theorem, n variables, m fundamental dimensions

(ΔP)πr2=μdvdr(2πrL)(\Delta P)\pi r^2 = -\mu\dfrac{dv}{dr}(2\pi r L)

Derivation step: Deriving Hagen-Poiseuille from a Force Balance

v(r)=ΔP4μL(R2r2),Q=πΔPR48μL=πΔPD4128μLv(r) = \dfrac{\Delta P}{4\mu L}(R^2 - r^2), \qquad Q = \dfrac{\pi \Delta P R^4}{8\mu L} = \dfrac{\pi \Delta P D^4}{128\mu L}

Derivation step: Deriving Hagen-Poiseuille from a Force Balance

Heat Transfer

17 formulas · used across 15 PYQ questions tagged this topic · Open the full topic guide

A=QU×LMTDA = \dfrac{Q}{U \times \text{LMTD}}

Required heat transfer area, given duty Q and overall coefficient U, apply an F-factor correction for multi-pass exchangers

Also in: Heat Exchanger Area, Lmtd

q=kAdTdxq = -kA\dfrac{dT}{dx}

Fourier's law of conduction; k = thermal conductivity, A = area normal to flow

Q=kA(T1T2)LQ = \dfrac{kA(T_1-T_2)}{L}

Steady conduction through a plane wall of thickness L

Q=2πkL(T1T2)ln(r2/r1)Q = \dfrac{2\pi k L (T_1-T_2)}{\ln(r_2/r_1)}

Steady radial conduction through a cylindrical wall

Rcond=LkA,Rconv=1hAR_{cond} = \dfrac{L}{kA}, \quad R_{conv} = \dfrac{1}{hA}

Thermal resistances, add in series for composite walls

q=hA(TsT)q = hA(T_s - T_\infty)

Newton's law of cooling for convective heat flux

rc=khr_c = \dfrac{k}{h}

Critical radius of insulation for a cylinder, adding insulation below rc increases heat loss

Bi=hLckBi = \dfrac{hL_c}{k}

Biot number, ratio of internal conductive to external convective resistance

Fo=αtLc2Fo = \dfrac{\alpha t}{L_c^2}

Fourier number, dimensionless time for unsteady conduction problems

Nu=hLkNu = \dfrac{hL}{k}

Nusselt number, ratio of convective to conductive heat transfer

Nu=0.023Re0.8PrnNu = 0.023\,Re^{0.8}Pr^{n}

Dittus-Boelter correlation for turbulent flow in a pipe (n = 0.4 heating, 0.3 cooling)

ΔTlm=ΔT1ΔT2ln(ΔT1/ΔT2)\Delta T_{lm} = \dfrac{\Delta T_1 - \Delta T_2}{\ln(\Delta T_1/\Delta T_2)}

Log mean temperature difference (LMTD) between hot and cold streams

ε=QactualQmax,NTU=UACmin\varepsilon = \dfrac{Q_{actual}}{Q_{max}}, \quad NTU = \dfrac{UA}{C_{min}}

Effectiveness-NTU method, an alternative to LMTD when outlet temperatures are unknown

Eb=σT4E_b = \sigma T^4

Stefan-Boltzmann law for black-body emissive power (σ = 5.67×10⁻⁸ W/m²K⁴)

Q=εσA(T14T24)Q = \varepsilon \sigma A (T_1^4 - T_2^4)

Radiative heat exchange between a grey surface and its surroundings

dQ=m˙hcp,hdTh=±m˙ccp,cdTc=U(ThTc)dAdQ = -\dot m_h c_{p,h}\,dT_h = \pm\dot m_c c_{p,c}\,dT_c = U(T_h - T_c)\,dA

Derivation step: Deriving LMTD from a Differential Energy Balance

Q=UAΔT1ΔT2ln(ΔT1/ΔT2)=UAΔTlmQ = UA \cdot \dfrac{\Delta T_1 - \Delta T_2}{\ln(\Delta T_1/\Delta T_2)} = UA \cdot \Delta T_{lm}

Derivation step: Deriving LMTD from a Differential Energy Balance

Mass Transfer

16 formulas · used across 16 PYQ questions tagged this topic · Open the full topic guide

log10(P)=ABC+T\log_{10}(P^{*}) = A - \dfrac{B}{C+T}

Antoine equation for pure-component vapor pressure (T in °C, constants from Perry's Handbook)

Also in: Antoine

xiPi=P\sum x_i P_i^{*} = P

Bubble point condition for a liquid mixture at total pressure P

Also in: Antoine

NA=DABdCAdzN_A = -D_{AB}\dfrac{dC_A}{dz}

Fick's first law of molecular diffusion (add bulk-flow term for diffusion through a stagnant film)

pA=xAPAp_A = x_A P_A^{*}

Raoult's law, partial pressure of component A over an ideal liquid mixture

α=yA/xAyB/xB\alpha = \dfrac{y_A/x_A}{y_B/x_B}

Relative volatility, the key parameter driving distillation separability

yiPPi=1\sum \dfrac{y_i P}{P_i^{*}} = 1

Dew point condition for a vapor mixture at total pressure P

NA=Ky(yAyA)=Kx(xAxA)N_A = K_y(y_A - y_A^{*}) = K_x(x_A^{*} - x_A)

Two-film theory, flux written in terms of overall gas- or liquid-phase driving force

1Ky=1ky+mkx\dfrac{1}{K_y} = \dfrac{1}{k_y} + \dfrac{m}{k_x}

Overall mass transfer coefficient combining individual gas- and liquid-film resistances (m = local slope of equilibrium line); Derivation step: Building the Overall Mass Transfer Coefficient from Two Films

q=qmaxKC1+KCq = \dfrac{q_{max} K C}{1 + K C}

Langmuir adsorption isotherm, monolayer equilibrium loading q vs. fluid concentration C

q=KC1/nq = K C^{1/n}

Freundlich adsorption isotherm, empirical power-law equilibrium relationship

tc=(W1Wc)LsARct_c = \dfrac{(W_1 - W_c) L_s}{A R_c}

Constant-rate drying time, from initial moisture W1 down to critical moisture Wc

tf=LsARcWcln ⁣(WcW2)t_f = \dfrac{L_s}{A R_c} W_c \ln\!\left(\dfrac{W_c}{W_2}\right)

Falling-rate drying time (linear falling-rate assumption), from Wc down to final moisture W2

H=1829pwPpwH = \dfrac{18}{29}\cdot\dfrac{p_w}{P - p_w}

Humidity (kg water vapor per kg dry air) from water vapor partial pressure pw and total pressure P

F=CP+2F = C - P + 2

Gibbs phase rule, degrees of freedom F for C components and P phases, used to check VLE problem consistency; Gibbs' phase rule, degrees of freedom F for C components and P phases

Also in: Thermodynamics

NA=ky(yyi)=kx(xix)N_A = k_y(y - y_i) = k_x(x_i - x)

Derivation step: Building the Overall Mass Transfer Coefficient from Two Films

yn+1=LVxn+DVxD=RR+1xn+xDR+1y_{n+1} = \dfrac{L}{V}x_n + \dfrac{D}{V}x_D = \dfrac{R}{R+1}x_n + \dfrac{x_D}{R+1}

Derivation step: Why the McCabe-Thiele Operating Line Is Linear

Mechanical Operations

12 formulas · used across 11 PYQ questions tagged this topic · Open the full topic guide

ϕs=surface area of a sphere of equal volumeactual surface area of particle\phi_s = \dfrac{\text{surface area of a sphere of equal volume}}{\text{actual surface area of particle}}

Sphericity, a shape factor equal to 1 for a perfect sphere

vt=gdp2(ρpρf)18μv_t = \dfrac{g d_p^2 (\rho_p - \rho_f)}{18\mu}

Stokes' law terminal settling velocity (valid for particle Reynolds number < 1)

Rep=dpvtρfμRe_p = \dfrac{d_p v_t \rho_f}{\mu}

Particle Reynolds number, checks whether Stokes' law (creeping flow) applies

dVdt=A2ΔPμ(αcV+ARm)\dfrac{dV}{dt} = \dfrac{A^2 \Delta P}{\mu(\alpha c V + A R_m)}

Cake filtration rate equation (α = specific cake resistance, c = mass solids/volume filtrate, Rm = medium resistance)

tV=μαc2A2ΔPV+μRmAΔP\dfrac{t}{V} = \dfrac{\mu \alpha c}{2A^2\Delta P}V + \dfrac{\mu R_m}{A\Delta P}

Linearized constant-pressure filtration equation, plot t/V vs. V to extract α and Rm

dEdL=KLn\dfrac{dE}{dL} = -K L^{-n}

General size-reduction energy law; n = 2 (Rittinger), n = 1 (Kick), n = 1.5 (Bond)

W=Wi(1dp21dp1)W = W_i\left(\dfrac{1}{\sqrt{d_{p2}}} - \dfrac{1}{\sqrt{d_{p1}}}\right)

Bond's law for grinding work, using the work index Wi

vmf:  ΔPErgun(vmf)=(ρpρf)g(1εmf)Lv_{mf}: \; \Delta P_{Ergun}(v_{mf}) = (\rho_p-\rho_f)g(1-\varepsilon_{mf})L

Minimum fluidization velocity, found by equating Ergun-equation pressure drop to the bed's net weight per unit area

Np=PρN3D5N_p = \dfrac{P}{\rho N^3 D^5}

Power number for a stirred-tank agitator (P = power, N = impeller speed, D = impeller diameter)

ηscreen=oversize recovered in overflowoversize in feed×undersize recovered in underflowundersize in feed\eta_{screen} = \dfrac{\text{oversize recovered in overflow}}{\text{oversize in feed}} \times \dfrac{\text{undersize recovered in underflow}}{\text{undersize in feed}}

Overall screen effectiveness combining oversize and undersize recovery

π6dp3ρpg=π6dp3ρfg+3πμdpvt\dfrac{\pi}{6}d_p^3 \rho_p g = \dfrac{\pi}{6}d_p^3 \rho_f g + 3\pi\mu d_p v_t

Derivation step: Deriving Stokes' Law from a Force Balance on a Settling Sphere

vt=gdp2(ρpρf)18μv_t = \dfrac{g d_p^2(\rho_p - \rho_f)}{18\mu}

Derivation step: Deriving Stokes' Law from a Force Balance on a Settling Sphere

Separations

Absorption Extraction

9 formulas · Open the full topic guide

pA=HxAp_A = H x_A

Henry's law, equilibrium partial pressure of dilute solute A, H = Henry's constant

y=LGx+(y2LGx2)y = \dfrac{L}{G}x + \left(y_2 - \dfrac{L}{G}x_2\right)

Absorption operating line from an overall mass balance (L = liquid, G = gas molar flow rate)

(LG)min:operating line touches equilibrium curve\left(\dfrac{L}{G}\right)_{min}: \text{operating line touches equilibrium curve}

Minimum liquid-to-gas ratio, analogous to minimum reflux in distillation

Z=HTU×NTUZ = HTU \times NTU

Packed column height from the height and number of transfer units

NTU=y2y1dyyyNTU = \int_{y_2}^{y_1} \dfrac{dy}{y - y^{*}}

Number of transfer units, a driving-force integral over the tower

HTU=GKyaSHTU = \dfrac{G}{K_y a S}

Height of a transfer unit, using the overall gas-phase mass transfer coefficient Ky and packing interfacial area a

m=ysolutexsolutem = \dfrac{y_{solute}}{x_{solute}}

Distribution (partition) coefficient for liquid-liquid extraction, analogous to Henry's constant

E=mVsolventLfeedE = \dfrac{m V_{solvent}}{L_{feed}}

Extraction factor, analogous to the absorption/stripping factor, governs recovery in a multistage cascade

Gy+Lx2=Gy2+Lx    y=LG(xx2)+y2Gy + Lx_2 = Gy_2 + Lx \;\Rightarrow\; y = \dfrac{L}{G}(x - x_2) + y_2

Derivation step: Deriving the Absorption Operating Line from an Overall Balance

Distillation

9 formulas · used across 5 PYQ questions tagged this topic · Open the full topic guide

αAB=yA/xAyB/xB\alpha_{AB} = \dfrac{y_A/x_A}{y_B/x_B}

Relative volatility, the driving parameter for how easily a binary mixture separates by distillation

y=αx1+(α1)xy = \dfrac{\alpha x}{1+(\alpha-1)x}

Equilibrium curve for a binary system with constant relative volatility α

yn+1=RR+1xn+xDR+1y_{n+1} = \dfrac{R}{R+1}x_n + \dfrac{x_D}{R+1}

Rectifying-section operating line, R = reflux ratio = L/D

ym=LVxm1WVxWy_m = \dfrac{L'}{V'}x_{m-1} - \dfrac{W}{V'}x_W

Stripping-section operating line (L', V' = liquid/vapor flow below the feed stage)

q=heat to vaporize 1 mol of feed at feed-plate conditionsmolar latent heat of feedq = \dfrac{\text{heat to vaporize 1 mol of feed at feed-plate conditions}}{\text{molar latent heat of feed}}

q-line parameter, q = 1 for saturated liquid feed, q = 0 for saturated vapor feed

y=qq1xxFq1y = \dfrac{q}{q-1}x - \dfrac{x_F}{q-1}

q-line equation on the y-x diagram, passing through (xF, xF)

ln(x1x2)/(α1)  +  ln(1x21x1)=lnL1L2\ln\left(\dfrac{x_1}{x_2}\right)\bigg/\left(\alpha-1\right) \;+\; \ln\left(\dfrac{1-x_2}{1-x_1}\right) = \ln\dfrac{L_1}{L_2}

Rayleigh equation for batch (differential) distillation with constant relative volatility

Nmin=ln[xD1xD1xWxW]lnαN_{min} = \dfrac{\ln\left[\dfrac{x_D}{1-x_D}\cdot\dfrac{1-x_W}{x_W}\right]}{\ln\alpha}

Fenske equation, minimum theoretical stages at total reflux (Nmin + 1 including the reboiler)

Rmin=1α1[xDxFα1xD1xF]R_{min} = \dfrac{1}{\alpha - 1}\left[\dfrac{x_D}{x_F} - \alpha\dfrac{1-x_D}{1-x_F}\right]

Underwood shortcut estimate for minimum reflux ratio (saturated liquid feed case)

Drying Humidification

9 formulas · Open the full topic guide

H=1829pwPpwH = \dfrac{18}{29}\cdot\dfrac{p_w}{P-p_w}

Absolute humidity from water vapor partial pressure pw and total pressure P

Also in: Psychrometrics

%RH=pwpw×100\%RH = \dfrac{p_w}{p_w^{*}} \times 100

Relative humidity, ratio of actual to saturation vapor pressure at the same temperature

%H=HHs×100\%H = \dfrac{H}{H_s} \times 100

Percentage humidity, ratio of actual to saturation humidity at the same temperature

vH=(129+H18)RT/Pv_H = \left(\dfrac{1}{29} + \dfrac{H}{18}\right)RT/P

Humid volume, volume of moist air per unit mass of dry air

TdbTwbkyλh(HsH)/ky  (air-water system: TwbTas)T_{db} - T_{wb} \approx \dfrac{k_y \lambda}{h}(H_s - H)\Big/k_y \;\text{(air-water system: } T_{wb} \approx T_{as}\text{)}

Wet-bulb depression relates to humidity driving force via the psychrometric ratio h/(ky·cs), ≈ 1 for air-water

Rc=Ls(W1Wc)AtcR_c = \dfrac{L_s(W_1-W_c)}{A\,t_c}

Constant-rate drying, rate Rc from initial moisture W1 to critical moisture Wc over time tc

tc=Ls(W1Wc)ARct_c = \dfrac{L_s(W_1-W_c)}{AR_c}

Time to complete the constant-rate period

tf=LsWcARcln ⁣(WcW2)t_f = \dfrac{L_s W_c}{AR_c}\ln\!\left(\dfrac{W_c}{W_2}\right)

Time for the (linear) falling-rate period, from Wc down to final moisture W2

LsAdWdt=RcWcW    tf=LsWcARcln ⁣(WcW2)-\dfrac{L_s}{A}\dfrac{dW}{dt} = \dfrac{R_c}{W_c}W \;\Rightarrow\; t_f = \dfrac{L_s W_c}{AR_c}\ln\!\left(\dfrac{W_c}{W_2}\right)

Derivation step: Why the Falling-Rate Drying Time Uses a Logarithmic Form

Evaporation Crystallization

6 formulas · Open the full topic guide

Sλs=Vλv+(sensible heat terms)S\lambda_s = V\lambda_v + \text{(sensible heat terms)}

Single-effect evaporator enthalpy balance, steam S (latent heat λs) supplies the latent heat to vaporize V (latent heat λv), plus any feed preheating

Steam economy=VtotalS\text{Steam economy} = \dfrac{V_{total}}{S}

Kilograms of total vapor produced per kilogram of live steam fed, approaches N (number of effects) for well-designed multiple-effect trains

Tb,solution=Tb,solvent+BPET_{b,solution} = T_{b,solvent} + BPE

Boiling point elevation, read from Dühring's chart or correlation for the specific solute-solvent system

y=mx+c (Du¨hring line)y = mx + c\ \text{(Dühring line)}

Dühring's rule, solution boiling point plotted linearly against solvent boiling point at constant concentration

FxF=LxL+CxCF x_F = L x_L + C x_C

Overall solute mass balance for a crystallizer, feed F, mother liquor L (at the solubility limit xL), crystals C (composition xC, may include water of hydration)

C=FxFxLxCxL (simplified, anhydrous crystals)C = F\cdot\dfrac{x_F - x_L}{x_C - x_L}\ \text{(simplified, anhydrous crystals)}

Crystal yield from a mass balance when the crystals are anhydrous (no water of crystallization)

Reactions & Control

Chemical Reaction Engineering

11 formulas · used across 27 PYQ questions tagged this topic · Open the full topic guide

rA=kCAn-r_A = k C_A^n

Power-law rate expression; n = reaction order, k = rate constant

k=AeEa/RTk = A e^{-E_a/RT}

Arrhenius equation, temperature dependence of the rate constant

VCSTR=FA0XrAV_{CSTR} = \dfrac{F_{A0}X}{-r_A}

CSTR design equation, exit conditions apply throughout the whole reactor volume

VPFR=FA00XdXrAV_{PFR} = F_{A0}\int_0^X \dfrac{dX}{-r_A}

PFR design equation, conditions change continuously along the reactor length

tbatch=NA00XdX(rA)Vt_{batch} = N_{A0}\int_0^X \dfrac{dX}{(-r_A)V}

Batch reactor design equation, time required for a given conversion

SD/U=rDrUS_{D/U} = \dfrac{r_D}{r_U}

Instantaneous selectivity of a desired product D over an undesired product U in parallel/series reactions

τ=Vv0\tau = \dfrac{V}{v_0}

Space time, the ideal residence time based on volumetric flow rate v0

tˉ=0tE(t)dt\bar t = \int_0^{\infty} t\,E(t)\,dt

Mean residence time from the residence time distribution E(t)

ϕ=LkDeff\phi = L\sqrt{\dfrac{k}{D_{eff}}}

Thiele modulus, compares reaction rate to internal (pore) diffusion rate in a catalyst pellet

η=actual rate with pore diffusionrate at surface conditions\eta = \dfrac{\text{actual rate with pore diffusion}}{\text{rate at surface conditions}}

Catalyst effectiveness factor, approaches 1 at low Thiele modulus, 1/φ at high Thiele modulus

CA=CA0(1X)C_{A} = C_{A0}(1-X)

Concentration in terms of conversion for a constant-volume (or constant-density) system

Process Calculations

10 formulas · Open the full topic guide

InOut+GenerationConsumption=Accumulation\text{In} - \text{Out} + \text{Generation} - \text{Consumption} = \text{Accumulation}

General balance equation; for steady, non-reactive systems this reduces to In = Out

xi=nijnjx_i = \dfrac{n_i}{\sum_j n_j}

Mole (or mass) fraction of component i in a stream

Overall conversion=fresh feed reactedfresh feed in\text{Overall conversion} = \dfrac{\text{fresh feed reacted}}{\text{fresh feed in}}

Overall conversion across a recycle system, always based on fresh feed, not reactor-inlet feed

Single-pass conversion=reacted per passfeed to reactor\text{Single-pass conversion} = \dfrac{\text{reacted per pass}}{\text{feed to reactor}}

Per-pass conversion is always lower than overall conversion when unreacted feed is recycled

% excess air=air suppliedair theoreticalair theoretical×100\%\text{ excess air} = \dfrac{\text{air supplied} - \text{air theoretical}}{\text{air theoretical}} \times 100

Excess air relative to the stoichiometric (theoretical) requirement for complete combustion

CxHy+(x+y4)O2xCO2+y2H2OC_xH_y + \left(x + \dfrac{y}{4}\right)O_2 \rightarrow xCO_2 + \dfrac{y}{2}H_2O

Generic hydrocarbon combustion stoichiometry used to find theoretical O2/air

DOF=NunknownsNindependent equationsDOF = N_{unknowns} - N_{independent\ equations}

Degrees of freedom; DOF = 0 means the problem is exactly (and uniquely) solvable

Q=ΔH=niTrefTCp,idTQ = \Delta H = \sum n_i \int_{T_{ref}}^{T} C_{p,i}\,dT

Sensible heat change of a stream from reference temperature to T

ΔHrxn=νpΔHf,pνrΔHf,r\Delta H_{rxn}^{\circ} = \sum \nu_p \Delta H_{f,p}^{\circ} - \sum \nu_r \Delta H_{f,r}^{\circ}

Standard heat of reaction from standard enthalpies of formation (Hess's law)

Purge fraction=purge streamrecycle stream before splitPurge\ fraction = \dfrac{\text{purge stream}}{\text{recycle stream before split}}

Fraction of the recycle loop continuously bled off to control inert buildup

Process Control

10 formulas · used across 15 PYQ questions tagged this topic · Open the full topic guide

G(s)=Y(s)X(s)=Kτs+1G(s) = \dfrac{Y(s)}{X(s)} = \dfrac{K}{\tau s + 1}

Standard first-order transfer function; K = steady-state gain, τ = time constant

y(t)=KA(1et/τ)y(t) = KA\left(1 - e^{-t/\tau}\right)

First-order step response to a step input of magnitude A

G(s)=Kτ2s2+2ζτs+1G(s) = \dfrac{K}{\tau^2 s^2 + 2\zeta\tau s + 1}

Standard second-order transfer function; ζ = damping ratio (ζ < 1 underdamped, oscillatory)

G(s)=Keθsτs+1G(s) = \dfrac{Ke^{-\theta s}}{\tau s + 1}

FOPDT (first-order-plus-dead-time) model; θ = dead time / transport delay

Y(s)Ysp(s)=GcGpGf1+GcGpGfGm\dfrac{Y(s)}{Y_{sp}(s)} = \dfrac{G_cG_pG_f}{1+G_cG_pG_fG_m}

Standard closed-loop (setpoint-tracking) transfer function for a unity-feedback control loop

u(t)=Kc[e(t)+1τI0tedt+τDdedt]u(t) = K_c\left[e(t) + \dfrac{1}{\tau_I}\int_0^t e\,dt + \tau_D\dfrac{de}{dt}\right]

PID controller action in the time domain (Kc = controller gain, τI = integral time, τD = derivative time)

Offset=limt[ysp(t)y(t)]\text{Offset} = \lim_{t\to\infty}\left[y_{sp}(t) - y(t)\right]

Steady-state offset, nonzero for proportional-only control under a sustained load change, zero once integral action is added

Kcu,Pu    Kc=0.6Kcu,  τI=Pu/2,  τD=Pu/8K_{cu}, P_u \;\rightarrow\; K_c = 0.6K_{cu},\; \tau_I = P_u/2,\; \tau_D = P_u/8

Ziegler-Nichols closed-loop (ultimate gain) PID tuning rule

VρcpdTdt=Fρcp(TiT)    τdTdt+T=Ti,τ=VFV\rho c_p\dfrac{dT}{dt} = F\rho c_p(T_i - T) \;\Rightarrow\; \tau\dfrac{dT^{\prime}}{dt} + T^{\prime} = T_i^{\prime}, \quad \tau = \dfrac{V}{F}

Derivation step: From a Stirred-Tank Energy Balance to a First-Order Transfer Function

τsT(s)+T(s)=Ti(s)    T(s)Ti(s)=1τs+1\tau s\,T^{\prime}(s) + T^{\prime}(s) = T_i^{\prime}(s) \;\Rightarrow\; \dfrac{T^{\prime}(s)}{T_i^{\prime}(s)} = \dfrac{1}{\tau s + 1}

Derivation step: From a Stirred-Tank Energy Balance to a First-Order Transfer Function

Thermodynamics

13 formulas · used across 18 PYQ questions tagged this topic · Open the full topic guide

F=CP+2F = C - P + 2

Gibbs phase rule, degrees of freedom F for C components and P phases, used to check VLE problem consistency; Gibbs' phase rule, degrees of freedom F for C components and P phases

Also in: Mass Transfer

ΔU=QW\Delta U = Q - W

First law for a closed system (W = work done by the system)

ΔH=ΔU+Δ(PV)\Delta H = \Delta U + \Delta(PV)

Enthalpy, the natural energy variable for steady-flow open systems

dSδQTdS \geq \dfrac{\delta Q}{T}

Second law, equality for reversible processes, strict inequality for irreversible ones

PV=ZRTPV = ZRT

Real-gas equation of state with compressibility factor Z (Z = 1 for ideal gas)

Z=1+BPRTZ = 1 + \dfrac{BP}{RT}

Truncated virial equation of state using the second virial coefficient B

fi=ϕiPf_i = \phi_i P

Fugacity of a pure gas via the fugacity coefficient φ (φ → 1 as P → 0)

f^iL=xiγifi\hat{f}_i^{L} = x_i \gamma_i f_i^{\circ}

Fugacity of component i in a non-ideal liquid mixture using activity coefficient γ_i

Ki=yixiK_i = \dfrac{y_i}{x_i}

Vapor-liquid equilibrium K-value for component i

ΔGrxn=RTlnK\Delta G_{rxn}^{\circ} = -RT\ln K

Standard Gibbs free energy of reaction and the equilibrium constant K

dlnKdT=ΔHrxnRT2\dfrac{d\ln K}{dT} = \dfrac{\Delta H_{rxn}^{\circ}}{RT^2}

Van't Hoff equation, how K shifts with temperature (integrate for a two-point estimate)

PVn=const.PV^{n} = \text{const.}

Polytropic process path for an ideal gas (n = 1 isothermal, n = γ isentropic, n = 0 isobaric)

νiμi=0    ΔGrxn=RTlnK,K=i(a^i)νi\sum \nu_i \mu_i = 0 \;\Rightarrow\; \Delta G_{rxn}^{\circ} = -RT\ln K, \qquad K = \prod_i (\hat a_i)^{\nu_i}

Derivation step: From the Second Law to the Equilibrium Constant

Applied

Chemical Technology

6 formulas · used across 9 PYQ questions tagged this topic · Open the full topic guide

N2+3H2450°C, 200 barFe catalyst2NH3N_2 + 3H_2 \underset{Fe\ catalyst}{\overset{450°C,\ 200\ bar}{\rightleftharpoons}} 2NH_3

Haber-Bosch ammonia synthesis, exothermic, so high pressure (not high temperature) favors conversion by Le Chatelier's principle

2NaCl+2H2OelectrolysisCl2+H2+2NaOH2NaCl + 2H_2O \xrightarrow{\text{electrolysis}} Cl_2 + H_2 + 2NaOH

Chlor-alkali electrolysis, the overall reaction across the membrane/diaphragm cell

S+O2SO2,2SO2+O2V2O5, 450°C2SO3,SO3+H2SO4H2S2O7H2O2H2SO4S + O_2 \rightarrow SO_2, \quad 2SO_2 + O_2 \xrightarrow{V_2O_5,\ 450°C} 2SO_3, \quad SO_3 + H_2SO_4 \rightarrow H_2S_2O_7 \xrightarrow{H_2O} 2H_2SO_4

Contact process, SO3 is absorbed into concentrated acid (forming oleum) then diluted, not absorbed directly into water

CaCO3+clay1450°Cclinker (Ca3SiO5,Ca2SiO4)+CO2CaCO_3 + \text{clay} \xrightarrow{1450°C} \text{clinker (}Ca_3SiO_5, Ca_2SiO_4\text{)} + CO_2

Cement clinkering reaction in the rotary kiln

2NH3+CO2NH2COONH4H2ONH2CONH2 (urea)2NH_3 + CO_2 \rightarrow NH_2COONH_4 \xrightarrow{-H_2O} NH_2CONH_2\ (\text{urea})

Urea synthesis via the ammonium carbamate intermediate

nCH2=CH2catalyst(CH2CH2)nnCH_2=CH_2 \xrightarrow{\text{catalyst}} (-CH_2-CH_2-)_n

Addition polymerization of ethylene to polyethylene

Engineering Mathematics

11 formulas · used across 28 PYQ questions tagged this topic · Open the full topic guide

det(AλI)=0\det(A - \lambda I) = 0

Characteristic equation, solve for eigenvalues λ of matrix A

(AλI)v=0(A-\lambda I)v = 0

Eigenvector equation, solve for the eigenvector v corresponding to eigenvalue λ

f=(fx,fy,fz)\nabla f = \left(\dfrac{\partial f}{\partial x}, \dfrac{\partial f}{\partial y}, \dfrac{\partial f}{\partial z}\right)

Gradient of a scalar field, points in the direction of steepest increase

Du^f=fu^D_{\hat u}f = \nabla f \cdot \hat u

Directional derivative of f in the direction of unit vector û

z=reiθ=r(cosθ+isinθ)z = re^{i\theta} = r(\cos\theta + i\sin\theta)

Polar/exponential form of a complex number (Euler's formula)

y+ay+by=0    y=C1em1x+C2em2xy'' + a y' + by = 0 \;\Rightarrow\; y = C_1e^{m_1x}+C_2e^{m_2x}

General solution of a second-order linear homogeneous ODE with constant coefficients (distinct real roots m1, m2 of the auxiliary equation)

x2y+axy+by=0x^2 y^{\prime\prime} + ax y^{\prime} + by = 0

Euler-Cauchy equation, solved via the substitution y = x^m, giving an algebraic equation in m

xn+1=xnf(xn)f(xn)x_{n+1} = x_n - \dfrac{f(x_n)}{f^{\prime}(x_n)}

Newton-Raphson iteration for root-finding, converges quadratically near a simple root

abf(x)dxh2[f(x0)+2i=1n1f(xi)+f(xn)]\int_a^b f(x)\,dx \approx \dfrac{h}{2}\left[f(x_0)+2\sum_{i=1}^{n-1}f(x_i)+f(x_n)\right]

Trapezoidal rule for numerical integration, step size h = (b−a)/n

P(AB)=P(BA)P(A)P(B)P(A|B) = \dfrac{P(B|A)P(A)}{P(B)}

Bayes' theorem for conditional probability

εn+1f(x)2f(x)εn2\varepsilon_{n+1} \approx \dfrac{f^{\prime\prime}(x^{*})}{2f^{\prime}(x^{*})}\,\varepsilon_n^2

Derivation step: Why Newton-Raphson Converges Quadratically Near a Simple Root

Plant Design Economics

9 formulas · used across 6 PYQ questions tagged this topic · Open the full topic guide

C2C1=(S2S1)0.6\dfrac{C_2}{C_1} = \left(\dfrac{S_2}{S_1}\right)^{0.6}

Six-tenths-factor rule for scaling equipment cost C with capacity S

C2=C1×I2I1C_2 = C_1 \times \dfrac{I_2}{I_1}

Cost index scaling, adjusts a historical cost C1 (index I1) to present-day cost C2 (index I2)

D=CSvnD = \dfrac{C - S_v}{n}

Straight-line depreciation, original cost C, salvage value Sv, useful life n years

Dt=C(1f)t1fD_t = C(1-f)^{t-1}f

Declining-balance depreciation in year t, with fixed depreciation rate f

PW=FW(1+i)nPW = \dfrac{FW}{(1+i)^n}

Present worth of a future cash flow FW, n years away, at interest rate i

Payback period=Fixed capital investmentAnnual cash flow (avg.)\text{Payback period} = \dfrac{\text{Fixed capital investment}}{\text{Annual cash flow (avg.)}}

Simple payback period, ignores the time value of money

NPV=t=0nCFt(1+i)tNPV = \sum_{t=0}^{n} \dfrac{CF_t}{(1+i)^t}

Net present value, sum of all discounted cash flows, including the initial (negative) investment at t = 0

NPV(IRR)=0NPV(IRR) = 0

Internal rate of return (IRR), the discount rate that makes NPV exactly zero

Break-even capacity: R(Q)=CF+CV(Q)\text{Break-even capacity: } R(Q) = C_F + C_V(Q)

Break-even point where total revenue R equals total cost (fixed CF plus variable CV) at production rate Q

Calculators

Antoine

7 formulas · Open the calculator

log10(P)=ABC+T\log_{10}(P^{*}) = A - \dfrac{B}{C+T}

Antoine equation for pure-component vapor pressure (T in °C, constants from Perry's Handbook)

Also in: Mass Transfer

pi=xiPip_i = x_i P_i^{*}

Raoult's law, partial pressure of component i in an ideal liquid mixture

dPdT=ΔHvapTΔV\dfrac{dP}{dT} = \dfrac{\Delta H_{vap}}{T\,\Delta V}

Clausius-Clapeyron equation, exact form relating the vapor-pressure curve slope to the enthalpy and volume change of vaporization

dPdT=ΔHvapPRT2\dfrac{dP}{dT} = \dfrac{\Delta H_{vap}\,P}{RT^2}

Clausius-Clapeyron equation with the ideal-gas approximation substituted for ΔV

ln(P)=ΔHvapRT+constant\ln(P^{*}) = -\dfrac{\Delta H_{vap}}{RT} + \text{constant}

Integrated Clausius-Clapeyron equation, the basis for the Antoine equation’s log-linear vapor pressure fit

α=PA/PB\alpha = P_A^{*}/P_B^{*}

Relative volatility of component A to B, estimated from their pure-component vapor pressures

xiPi=P\sum x_i P_i^{*} = P

Bubble point condition for a liquid mixture at total pressure P

Also in: Mass Transfer

Friction Factor

3 formulas · Open the calculator

ΔP=f(LD)(ρv22)\Delta P = f\left(\dfrac{L}{D}\right)\left(\dfrac{\rho v^2}{2}\right)

Darcy-Weisbach equation for frictional pressure drop (use the Moody chart for turbulent f)

Also in: Fluid Mechanics, Pressure Drop

1f=2log10(ε/D3.7+2.51Ref)\dfrac{1}{\sqrt f} = -2\log_{10}\left(\dfrac{\varepsilon/D}{3.7}+\dfrac{2.51}{Re\sqrt f}\right)

Colebrook equation for the Darcy friction factor in turbulent pipe flow (implicit in f, solved iteratively)

f=64/Ref = 64/Re

Darcy friction factor for fully-developed laminar pipe flow

Also in: Reynolds

Heat Exchanger Area

3 formulas · Open the calculator

Q=UAΔTlmQ = U A \,\Delta T_{lm}

Heat exchanger duty from the overall coefficient, area, and log mean temperature difference

A=QU×ΔTlmA = \dfrac{Q}{U \times \Delta T_{lm}}

Required heat transfer area, solved from duty Q, overall coefficient U, and LMTD

A=QU×LMTDA = \dfrac{Q}{U \times \text{LMTD}}

Required heat transfer area, given duty Q and overall coefficient U, apply an F-factor correction for multi-pass exchangers

Also in: Heat Transfer, Lmtd

Lmtd

12 formulas · Open the calculator

A=QU×LMTDA = \dfrac{Q}{U \times \text{LMTD}}

Required heat transfer area, given duty Q and overall coefficient U, apply an F-factor correction for multi-pass exchangers

Also in: Heat Exchanger Area, Heat Transfer

dQ=UΔTdAdQ = U\,\Delta T\,dA

Local heat duty across a differential exchanger area dA, driven by the local temperature difference

dTh=dQ/ChdT_h = -dQ/C_h

Differential temperature drop of the hot stream per unit heat transferred, C_h = hot-stream heat capacity rate

dTc=dQ/CcdT_c = -dQ/C_c

Differential temperature change of the cold stream per unit heat transferred, C_c = cold-stream heat capacity rate

Ch=m˙hCphC_h = \dot{m}_h Cp_h

Heat capacity rate of the hot stream (mass flow rate × specific heat)

Cc=m˙cCpcC_c = \dot{m}_c Cp_c

Heat capacity rate of the cold stream (mass flow rate × specific heat)

d(ΔT)=dQ(1Ch1Cc)d(\Delta T) = -dQ\left(\dfrac{1}{C_h} - \dfrac{1}{C_c}\right)

Change in the hot-cold temperature difference per unit heat transferred, combining both streams’ energy balances

d(ΔT)ΔT=U(1Ch1Cc)dA\dfrac{d(\Delta T)}{\Delta T} = -U\left(\dfrac{1}{C_h} - \dfrac{1}{C_c}\right)dA

Separated form of the LMTD derivation, integrating this over the exchanger area produces the logarithmic mean

Q=UAFLMTDcfQ = UAF \cdot \text{LMTD}_{cf}

Heat duty for a multi-pass/cross-flow exchanger, counter-flow LMTD corrected by the F-factor

Q=m˙CpΔTQ = \dot{m} Cp\,\Delta T

Sensible heat duty of a single stream from its flow rate, specific heat, and temperature change

(ΔT1+ΔT2)/2(\Delta T_1+\Delta T_2)/2

Arithmetic mean temperature difference, a simpler (but less accurate) alternative to LMTD when ΔT₁ and ΔT₂ are close

LMTD=ΔT1ΔT2ln(ΔT1/ΔT2)\text{LMTD} = \dfrac{\Delta T_1 - \Delta T_2}{\ln(\Delta T_1/\Delta T_2)}

Log mean temperature difference between the hot and cold streams of a heat exchanger

NPSH

5 formulas · Open the calculator

Patmρg+zsource=Psuctionρg+zpump+hf\dfrac{P_{atm}}{\rho g} + z_{source} = \dfrac{P_{suction}}{\rho g} + z_{pump} + h_f

Bernoulli energy balance from the suction source to the pump inlet, including friction loss h_f

hs=zsourcezpumph_s = z_{source} - z_{pump}

Static suction head, elevation of the liquid source above (or below) the pump centerline

Pv/ρgP_v/\rho g

Vapor pressure head, the liquid's vapor pressure expressed as a head, subtracted in the NPSH available calculation

NPSHa=PsuctionρgPvρg=PatmPvρg+hshfNPSH_a = \dfrac{P_{suction}}{\rho g} - \dfrac{P_v}{\rho g} = \dfrac{P_{atm}-P_v}{\rho g} + h_s - h_f

Net positive suction head available, expanded from suction-side pressure head down to atmospheric pressure, static head, and friction loss

NPSHa=PatmPvρg+hshfNPSH_a = \dfrac{P_{atm}-P_v}{\rho g} + h_s - h_f

Net positive suction head available, the usable margin above vapor pressure at the pump suction, must exceed the pump’s required NPSH to avoid cavitation

Pressure Drop

1 formula · Open the calculator

ΔP=f(LD)(ρv22)\Delta P = f\left(\dfrac{L}{D}\right)\left(\dfrac{\rho v^2}{2}\right)

Darcy-Weisbach equation for frictional pressure drop (use the Moody chart for turbulent f)

Also in: Fluid Mechanics, Friction Factor

Psychrometrics

2 formulas · Open the calculator

H=1829pwPpwH = \dfrac{18}{29}\cdot\dfrac{p_w}{P-p_w}

Absolute humidity from water vapor partial pressure pw and total pressure P

Also in: Drying Humidification

pw=pws(Twb)ApP(TdbTwb)p_w = p_{ws}(T_{wb}) - A_p P (T_{db}-T_{wb})

Modified psychrometer equation, actual water vapor partial pressure from wet-bulb and dry-bulb temperatures

Pump Power

4 formulas · Open the calculator

Phydraulic=m˙gH=ρQgHP_{hydraulic} = \dot{m} g H = \rho Q g H

Hydraulic (fluid) power delivered by a pump, from mass or volumetric flow rate and total head H

η=PhydraulicPbrake    Pbrake=Phydraulicη=ρQgHη\eta = \dfrac{P_{hydraulic}}{P_{brake}} \;\Rightarrow\; P_{brake} = \dfrac{P_{hydraulic}}{\eta} = \dfrac{\rho Q g H}{\eta}

Pump efficiency relates hydraulic power to shaft (brake) power, rearranged to solve for brake power

Phydraulic=ρgQHP_{hydraulic} = \rho g Q H

Hydraulic power in terms of fluid density, volumetric flow rate, and total head

Pbrake=Phydraulic/ηP_{brake} = P_{hydraulic}/\eta

Brake (shaft) power required, accounting for pump efficiency losses

Reynolds

11 formulas · Open the calculator

Re=ρvDμRe = \dfrac{\rho v D}{\mu}

Reynolds number, Re < 2100 laminar, 2100–4000 transitional, > 4000 turbulent (circular pipe)

Also in: Fluid Mechanics

ΔP=32μLvD2\Delta P = \dfrac{32\mu L v}{D^2}

Hagen-Poiseuille equation, laminar pressure drop in a pipe (Q = πΔPD⁴/128μL)

Also in: Fluid Mechanics

f=64/Ref = 64/Re

Darcy friction factor for fully-developed laminar pipe flow

Also in: Friction Factor

Re=vDνRe = \dfrac{vD}{\nu}

Reynolds number in terms of kinematic viscosity ν (equivalent to ρvD/μ)

Dh=4A/PD_h = 4A/P

Hydraulic diameter for non-circular ducts, 4× cross-sectional area over wetted perimeter, used in place of D in Re for non-circular flow

ρ(vt+vv)=p+μ2v\rho\left(\dfrac{\partial v}{\partial t} + v\cdot\nabla v\right) = -\nabla p + \mu \nabla^2 v

Navier-Stokes momentum equation for incompressible flow, the physical origin of the Reynolds number as a ratio of its inertial to viscous terms

x=x/L, v=v/U, t=tU/L, p=p/(ρU2)x^{*}=x/L,\ v^{*}=v/U,\ t^{*}=tU/L,\ p^{*}=p/(\rho U^2)

Dimensionless scaling variables used to non-dimensionalize the Navier-Stokes equation

vt+vv=p+μρUL2v\dfrac{\partial v^{*}}{\partial t^{*}} + v^{*}\cdot\nabla^{*} v^{*} = -\nabla^{*} p^{*} + \dfrac{\mu}{\rho U L}\nabla^{*2} v^{*}

Non-dimensionalized Navier-Stokes equation, the coefficient μ/(ρUL) that appears is 1/Re

InertialViscous=ρU2/LμU/L2=ρULμ=Re\dfrac{\text{Inertial}}{\text{Viscous}} = \dfrac{\rho U^2/L}{\mu U/L^2} = \dfrac{\rho U L}{\mu} = Re

Physical definition of the Reynolds number as the ratio of inertial to viscous forces in a flow

ΔP=128μLQπD4\Delta P = \dfrac{128\mu L Q}{\pi D^4}

Hagen-Poiseuille pressure drop for laminar flow in a circular pipe, in terms of volumetric flow rate Q

Re=ρvD/μRe = \rho v D/\mu

Reynolds number, ratio of inertial to viscous forces, determines laminar vs. turbulent flow regime

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