Chemegate

GATE 2026 Chemical Engineering, Q52 · Heat Transfer

The correct answer is 34.5 to 35.5.

Question

In a double pipe cocurrent heat exchanger, operating at steady state, oil (specific heat capacity = 2100 J kg1°C1)kg⁻¹ °C⁻¹) entering at 7 kg s1s⁻¹ at 100°C100°C is used to heat water (specific heat capacity = 4200 J kg1°C1)kg⁻¹ °C⁻¹) flowing at 3.5 kg s1s⁻¹ from 20°C20°C to 50°C.50°C. If the overall heat transfer coefficient is 291 W m2°C1,m⁻² °C⁻¹, the required heat transfer area (in m2)m²) is _____ (rounded off to one decimal place).

Official answer: 34.5 to 35.5

Why

GATE 2026 official key: 34.5 to 35.5. Q =3.5×4200×30=441= 3.5 \times 4200 \times 30 = 441 kW; oil exits at 70°C.70°C. Cocurrent LMTD = (80−20)/ln(80/20) 43.3°C.\approx 43.3°C. A =Q/(U×LMTD)=441000/(291×43.3)35.0m2.= Q/(U \times LMTD) = 441000/(291 \times 43.3) \approx 35.0 m².

Explanation cross-checked for consistency. Final answer matches the official IIT answer key.