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GATE 2026 Chemical Engineering, Q30 · Mechanical Operations

The correct answer is 4 to 4.2.

Question

Consider two successive screen sizes in the Tyler standard screen scale, viz. 150 meshes per inch and 200 meshes per inch. Their linear sizes of the openings are L150 and L200, respectively. If the value of L200 is 2.9×10−32.9 \times 10⁻³ inch, then the value of L150 (in inch) is _____ ×10−3 \times 10⁻³ (rounded off to one decimal place).

Official answer: 4 to 4.2

Why

GATE 2026 official key: 4.0 to 4.2. Successive Tyler screens have a fixed size ratio of 2,\sqrt{2}, so L150 = L200 ×2≈2.9×1.414≈4.1×10−3 \times \sqrt{2} \approx 2.9 \times 1.414 \approx 4.1 \times 10⁻³ inch.

Explanation cross-checked for consistency. Final answer matches the official IIT answer key.

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