Chemegate

GATE 2025 Chemical Engineering, Q65 · Mechanical Operations

The correct answer is 0.5 to 0.9.

Question

A wet solid of 100 kg containing 30 wt% moisture is to be dried to 2 wt% moisture in a tray dryer. The critical moisture content is 10 wt% and the equilibrium moisture content is 1 wt%. The drying rate during the constant rate period is 10kg/(hm2).10 kg/(h\cdot m²). The drying curve in the falling rate period is linear. If the drying area is 5m2,5 m², the time required for drying is ____ h (rounded off to 1 decimal place). Note: all the moisture values given are on dry-solid basis.

Official answer: 0.5 to 0.9

Why

GATE 2025 official key: 0.5 to 0.9 h. Dry solids Ls=100/1.3076.9L_{s} = 100/1.30 \approx 76.9 kg. Constant rate period: tc=Ls(X0Xc)/(ARc)0.31t_{c} = L_{s}(X₀−X_{c})/(A\cdot R_{c}) \approx 0.31 h. Falling rate period: tf=[Ls(XcX)/(ARc)]ln[(XcX)/(X2X)]0.30t_{f} = [L_{s}(X_{c}−X*)/(A\cdot R_{c})]\cdot ln[(X_{c}−X*)/(X₂−X*)] \approx 0.30 h. Total 0.61\approx 0.61 h.

Explanation cross-checked for consistency. Final answer matches the official IIT answer key.