Chemegate

GATE 2025 Chemical Engineering, Q53 · Heat Transfer

The correct answer is 38.5 to 39.1.

Question

An electrical wire of 2 mm diameter and 5 m length is insulated with a plastic layer of thickness 2 mm and thermal conductivity k = 0.1 W/(m·K). It is exposed to ambient air at 30°C.30°C. For a current of 5 A, the potential drop across the wire is 2 V. The air-side heat transfer coefficient is 20W/(m2K).20 W/(m²K). Neglecting the thermal resistance of the wire, the steady state temperature at the wire-insulation interface is ____ °C°C (rounded off to 1 decimal place).

Official answer: 38.5 to 39.1

Why

GATE 2025 official key: 38.5 to 39.1°C.39.1°C. Heat generated q' = IV/L = 10/5 = 2 W/m. R'_cond =ln(r2/r1)/(2πk)1.75,= ln(r₂/r₁)/(2πk) \approx 1.75, R'_conv =1/(h2πr2)2.65= 1/(h\cdot 2πr₂) \approx 2.65 (m·K/W). ΔT=\Delta T = q'(R'_cond+R'_conv) 8.8°C,\approx 8.8°C, so Tinterface30+8.838.8°C.T_{interface} \approx 30+8.8 \approx 38.8°C.

Explanation cross-checked for consistency. Final answer matches the official IIT answer key.