Chemegate

GATE 2026 Chemical Engineering, Q58 · Thermodynamics

The correct answer is 285.

Question

A gas mixture of 50 wt% argon and 50 wt% helium flows through a horizontal tube at 1 kg s1s⁻¹ and is heated from 300 K to 400 K at 1 bar (ideal gas, negligible KE/PE changes). Specific enthalpies (kJ kg1):kg⁻¹): Argon 348→400, Helium 1574→2092. At steady state, the heat input required (in kW) is ___________ (rounded off to the nearest integer).

Official answer: 285

Why

GATE 2026 official key: 285. Steady-flow energy balance (negligible KE/PE): Q =Σm˙iΔhi.= \Sigma ṁᵢ\Delta hᵢ. With 0.5 kg/s each of argon and helium: Q =0.5×(400348)+0.5×(20921574)=26+259=285= 0.5 \times (400−348) + 0.5 \times (2092−1574) = 26 + 259 = 285 kW.

Explanation cross-checked for consistency. Final answer matches the official IIT answer key.