Vapor pressure of water: 284 K → 1.28 kPa, 289 K → 1.80 kPa, 294 K → 2.50 kPa, 299 K → 3.40 kPa, 310 K → 6.40 kPa. An air and water vapor mixture at 100 kPa with a relative humidity of 20% has a dry-bulb temperature of 310 K. Assume latent heat of vaporization for water is 44 kJ mol⁻¹ and specific heat capacity of the air and water vapor mixture is 0.035 kJ mol⁻¹ K⁻¹. Which one of the following is closest to its wet-bulb temperature (in K)?

Question

Accepted Answer

The correct answer is B, 294. GATE 2026 official key: (B). Balancing the latent-heat driving force against the sensible-heat cooling with the given vapor-pressure data gives a wet-bulb temperature of about 294 K.