Chemegate

GATE 2026 Chemical Engineering, Q10 · General Aptitude

The correct answer is C, 7 − 4√2.

Question

Circle C1 with center O1 and radius r1 touches the square VWXY at points P and Q, while circle C2 with center O2 and radius r2 touches the square VWXY at points R and S. The two circles touch each other at T. Given r1 = 1 cm and VY = VW = 4 cm, r2 = _____ cm.

Figure for Q10 (General Aptitude, Geometry): Circle C1 with center O1 and radius r1 touches the square VWXY at points P and Q, while circle C2 wi…
  • A. 4324 − 3\sqrt{2}
  • B. 1+221 + 2\sqrt{2}
  • C. 7427 − 4\sqrt{2}
  • D. 5+325 + 3\sqrt{2}

Official answer: 7427 − 4\sqrt{2}

Why

GATE 2026 official key: (C). Solving the tangency conditions (O1O2 = r1+r2, each center offset r from its two adjacent sides) with r1 = 1 cm gives r2 =742= 7 − 4\sqrt{2} cm.

Explanation cross-checked for consistency. Final answer matches the official IIT answer key.