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GATE 2025 Chemical Engineering, Q64 · Reaction Engineering

The correct answer is 150.

Question

Consider the flowsheet shown in the figure for manufacturing C via the reaction A + B C in an isothermal CSTR. Pure A and pure B are fed, along with a recycle stream of R kmol/h. The split in the separator is perfect so that the recycle stream contains only A and B (no C) and the product stream is pure C. Let xix_{i} denote the mole fraction of species i (i = A, B, C) in the CSTR, which is operated in excess B with xB/xA=4.x_{B}/x_{A} = 4. The reaction is first-order in A with the reaction rate (rA)=kxxA,(−r_{A}) = k_{x}\cdot x_{A}, where kx=5.0kmol/(m3h).k_{x} = 5.0 kmol/(m³\cdot h). The reactor volume V in m3 is to be optimized to minimize the cost objective J = V + 0.25R, where R is the recycle rate in kmol/h. For a product rate P = 100 kmol/h, the optimum value of V is ____ m3 (rounded off to the nearest integer). Given: d/dz[z/(1−z)] =1/(1z)2.= 1/(1−z)².

Figure for Q64 (Reaction Engineering, Recycle Reactors): Consider the flowsheet shown in the figure for manufacturing C via the reaction A + B → C in an isot…

Official answer: 150

Why

GATE 2025 official key: 150. Minimizing J = V + 0.25R with the mole-balance constraint linking V, R and the fixed product rate P via the given derivative identity yields an optimum reactor volume of 150m3.150 m³.

Explanation cross-checked for consistency. Final answer matches the official IIT answer key.