Chemegate

GATE 2025 Chemical Engineering, Q55 · Mass Transfer

The correct answer is 4.2 to 4.6.

Question

Gas containing 0.8 mol% component A is to be scrubbed with pure water in a packed bed column to reduce the concentration of A to 0.1 mol% in the exit gas. The inlet gas and water flow rates are 0.1 kmol/s and 3.0 kmol/s, respectively. For the dilute system, both the operating and equilibrium curves are considered linear. If the slope of the equilibrium line is 24, the number of transfer units, based on the gas side, NOGN_{O}G is ____ (rounded off to 1 decimal place).

Official answer: 4.2 to 4.6

Why

GATE 2025 official key: 4.2 to 4.6. With mG/L =24×0.1/3=0.8,= 24 \times 0.1/3 = 0.8, the Colburn equation gives NOG=N_{O}G = [1/(1−0.8)]·ln[(1−0.8)(0.008/0.001)+0.8] =5×ln(2.4)4.38.= 5 \times ln(2.4) \approx 4.38.

Explanation cross-checked for consistency. Final answer matches the official IIT answer key.