Chemegate

GATE 2025 Chemical Engineering, Q40 · Mass Transfer

The correct answer is B, 14.

Question

500 mg of a dry adsorbent is added to a beaker containing 100 mL solution of concentration 100 mg phenol/(L solution). The adsorbent is separated out after 5 h of rigorous mixing. If the residual concentration in the solution after separating the adsorbent is 30 mg phenol/(L solution), the amount of phenol adsorbed (in mg per gram of dry adsorbent) is

  • A. 7
  • B. 14
  • C. 28
  • D. 18

Official answer: 14

Why

GATE 2025 official key: (B). Phenol adsorbed = (100−30) mg/L ×0.1 \times 0.1 L = 7 mg, over 0.5 g adsorbent = 7/0.5 = 14 mg/g.

Explanation cross-checked for consistency. Final answer matches the official IIT answer key.