Chemegate

GATE 2024 Chemical Engineering, Q55 · Thermodynamics

The correct answer is 1719 to 1730.

Question

Methane combusts with air in a furnace as CH4+2O2CH₄ + 2O₂ CO2+2H2O.CO₂ + 2H₂O. The heat of reaction ΔHrxn=880\Delta H_{rxn} = −880 kJ per mol CH4CH₄ and is assumed constant. The furnace is well-insulated and no other side reactions occur. All components behave as ideal gases with a constant molar heat capacity of 44J/(mol°C).44 J/(mol\cdot °C). Air is 20 mol% O2O₂ and 80 mol% N2.N₂. The air-fuel mixture enters the furnace at 50°C.50°C. The methane conversion X varies with the air-to-methane mole ratio, r, as X =10.1e2(rrs)= 1 − 0.1e^{−2(r−rs)} with 0.9rs \leq r \leq 1.1rs, where rs is the stoichiometric air-to-methane mole ratio. For r = 1.05rs, the exit flue gas temperature in °C,°C, rounded off to 1 decimal place, is ______

Official answer: 1719 to 1730

Why

GATE 2024 official key: 1719.0 to 1730.0. rs = 2/0.2 = 10 (mol air/mol CH4). At r=10.5: X =10.1e10.9632.= 1−0.1e⁻¹ \approx 0.9632. Basis 1 mol CH4: total moles = 1+10.5=11.5, unchanged by reaction (3→3 mol). Heat released =0.9632×880,000847,600= 0.9632 \times 880,000 \approx 847,600 J. Energy balance: 11.5×44×(Tf323)=84760011.5 \times 44 \times (Tf−323) = 847600 \Rightarrow Tf 1998.3\approx 1998.3 K 1725.3°C.\approx 1725.3°C.

Explanation cross-checked for consistency. Final answer matches the official IIT answer key.