Chemegate

GATE 2024 Chemical Engineering, Q36 · Fluid Mechanics

The correct answer is A, [(P1−P2)H²/(2μL)]·(1−(y/H)²) + (V/2)·((y/H)−1).

Question

Consider a steady, fully-developed, uni-directional laminar flow of an incompressible Newtonian fluid (viscosity μ)μ) between two infinitely long horizontal plates separated by a distance 2H, as shown in the figure. The flow is driven by the combined action of a pressure gradient and the motion of the bottom plate at y = −H in the negative x direction with speed V, relative to the stationary top plate at y = H. Given (P1−P2)/L > 0, where P1 and P2 are the pressures at two x locations separated by distance L. Which one of the following represents the x-component of the fluid velocity vector?

Figure for Q36 (Fluid Mechanics, Couette-Poiseuille Flow): Consider a steady, fully-developed, uni-directional laminar flow of an incompressible Newtonian flui…
  • A. [(P1P2)H2/(2μL)](1(y/H)2)+[(P1−P2)H²/(2μL)]\cdot (1−(y/H)²) + (V/2)·((y/H)−1)
  • B. [(P1P2)H2/(2μL)]((y/H)21)+[(P1−P2)H²/(2μL)]\cdot ((y/H)²−1) + (V/2)·((y/H)−1)
  • C. [(P1P2)H2/(2μL)]((y/H)21)[(P1−P2)H²/(2μL)]\cdot ((y/H)²−1) − (V/2)·((y/H)−1)
  • D. [(P1P2)H2/(2μL)](1(y/H)2)[(P1−P2)H²/(2μL)]\cdot (1−(y/H)²) − (V/2)·((y/H)−1)

Official answer: [(P1P2)H2/(2μL)](1(y/H)2)+[(P1−P2)H²/(2μL)]\cdot (1−(y/H)²) + (V/2)·((y/H)−1)

Why

GATE 2024 official key: (A). Solving μd2u/dy2=μ\cdot d²u/dy² = −(P1−P2)/L with u(H)=0 and u(−H)=−V gives u(y) =[(P1P2)H2/(2μL)](1(y/H)2)+= [(P1−P2)H²/(2μL)]\cdot (1−(y/H)²) + (V/2)·((y/H)−1).

Explanation cross-checked for consistency. Final answer matches the official IIT answer key.